IIT JEE , AIEEE Forum - Physics , Mechanics

srujana

It is not different from the ordinary projectile motion,except that the vectors are resolved along the chosen axes

Let the angle of inclination of the incline be $\alpha$ and the angle of projection to be $\theta$ with respect to the ground.

v=velocity of the projectile

Consider two axes X,Y along and perpendicular to the incline

Along X axis

$v_x=vcos(\theta-\alpha)$

$a_x=-gsin\alpha$

Along Yaxis

$v_y=vsin(\theta-\alpha)$

$a_y=-gcos\alpha$

Write the equations of motion along X and Y axes

$Range(x)=v_xt+\frac{1}{2}a_xt^2$

$Height(h)=v_yt+\frac{1}{2}a_yt^2$

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