IIT JEE , AIEEE Forum - Physics , Mechanics - A FORCE-ENERGY PROBLEM FOR EXPERTS

DON007

²hey frnd.........look

1/2mv²= c x²

differentiating .............we get........

1/2m * 2v (dv/dt)= 2cx(dx/dt)

(diffferentiating wrt time).........

mva = 2 c x v

cancelling v.........

a(tangential)= 2cx/m

a(radial)= mv²/ r =2cx²/r.............(using 1/2mv²=cx²)

now.........

A(TOTAL) = SQRT[ ( 2cx/m)² + ( 2cx²/r)²

hope u understand it.........

thanks