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What I do is, consider A.Ps of common differences 1 through 7 For 7, only one solution For 6, 3 solutions For 5, 5 solutions For 4, 7 solutions For 3, 9 solutions For 2, 11 solutions For 1, 13 solutions
So total of 49 favourable outcomes. And a total of 455 outcomes So answer's 7/65..
But allamraju's method is obviously much better..
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