Ans is 3/rt2.Since it is pf the form 0/0,Apply L'hospital's rule,then
-3(cosx+sinx)2(cosx-sinx)/-2cos2x=(3/2)[(cosx+sinx)2(cosx-sinx)/cos2x-sin2x].By cancelling (cosx-sinx) and one (cosx+sinx),it becomes (3/2)(cosx+sinx) which tends to 3/rt2 as x tends to pi/4
MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC.
Moderation Team
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