the answer is 2mvsin(theta) in projectile motion because no accleration acts in horizontal direction so horizontal component of velocity remain constant.so change in linear momentum take place due to change in vertical component of vel..i.e. vsin(theta) change in momentum = mvsin(theta)-mvsin(-theta) =2mvsin(theta) if i helped u then plz rate me plz
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if i helped u plzzzzz rate me,,,,,,,