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| Forum Index -> Integral Calculus -> View Full Question |
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sin2x = sin(5x-3x) = sin5xcos3x - sin3xcos5x sin2x/(sin3xsin5x) = (sin5xcos3x - sin3xcos5x)/(sin3xsin5x) = cot3x - cot5x Integrating it with respect to x we get ln(sec3x) - ln(sec5x) + c |
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Bipin Kumar Dubey Chemical Dept. IIT Kharagpur |
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