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[Post New]17 May 2008 23:57:23 IST
    Subject: 132
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spideyunlimited (4254)

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A wire of certain material is stretched slowly by ten percent. Its new resistance and specific resistance become respectively.....


Specific resistance = constant for a given material

For new R:
New Length = 1.1 L (110% of L)
Since Area of cross section is inversely proportional to length so
New Area of cross section = A/1.1

New Resistance = p l/a = p (1.1)^2 L / A
so new resistance is 1.21 times original resistance.
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- Gaurav Ragtah (spideyunlimited)
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