 Discussion Response Post to:
solve
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2008 12:09:55 IST
|
|
|
here is another solution.....
cos^2x/1+tanx
put tanx = t
sec^2xdx = dt,,,,now substitute,,,,,,
u will get cos^4x/1+t.....now we can write cos^4x = (cos^2x)^2
applying half angle formula of cos2x....we get cos^2x = 1+cos2x/2
now cos2x = 1-tan^2x/1+tan^2x....now substitute,,,,,,,this to question...
further solution is here....
http://www.goiit.com/posts/list/integration-integration-60360.htm
|
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
      
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
if i helped u plzzzzz rate me,,,,,,, |
this reply: 2 points
(with 0 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
