hi fren........1 more method integral of dx/(1-sin2x) here 1-sin2x can b written as 1-2sinx cosx..........k now multiply sec^2 x in both num n deno. so u ll get......integral of sec^2 x dx/(tan^2 x + 1 - 2 tanx) so........u can write it as....integral of sec^2 x dx/(1-tanx)^2 put tanx = t n u ll get the answer hope u got that : )
Moderation Team
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