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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 May 2008 19:46:49 IST
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See, just find the oxidation state of C in each case.
More the oxi state, more it is oxidised.
For finding oxi state, consider each bond to be ionic.
Now O>C>H(electronegativity)
So in R-COOH
Oxi state of C = +3 (+2 from C=O and +1 from C-OH)
And in CH2OH
oxi state of C= -1 ( -2 from 2 C-H bonds and +1 from C-OH)
So C is more oxidised in COOH
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