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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 May 2008 16:00:17 IST
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ur above statement can b rewritten as
[1 + 5(x-1)/{(x-2)(x-3)}]dx
= [1 + 10/(x-3) - 5/(x-2)]dx
on integration we will get
x + 10log(x-3) - 5log(x-2) +c
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this reply: 10 points
(with 2 
in 2 votes ) [?]
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