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trig eqns
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2tan2x - 5secx -1 = 0 2(sec2x - 1) - 5secx - 1 = 0 2sec2x - 5secx - 3 = 0 secx = -1/2,3 Since secx<= -1 or secx>= 1 Hence secx = 3 ( i.e in the 1st and 4th quadrant ) Hence it has 6 solutions in (0.6  )and one value in (6 ,6 + /2) i.e (6,13/2)Hence it has 7 solutions in (0,13 /2)Hence n = 13 |
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Bipin Kumar Dubey Chemical Dept. IIT Kharagpur |
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