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[Post New]20 May 2008 19:46:34 IST
    Subject: using lmvt prove
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RyuAmakusa (942)

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Olaaa!! Perrrfect answer. 154  [240 rates]
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@mukund i think that is not the statement of lmvt anyway now
applying lmvt beetween (0,x) x is any no. >0
f'(x)= f(x)-f(0)/x f(x)=ln(1+x)-x =>f'(x)=(ln(1+x)/x)-1 now ln function increases at a rate less than x so f'(x)<0=>ln(1+x)/x-1<0
=>ln(1+x)
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