sign up I login
 advanced
refer a friend - earn nickels!!

Ask & Discuss Questions with Community & Experts

Moderation Team
Ask iit jee aieee pet cbse icse state board experts Discussion Response Post to: MOTION
Forum Index -> Mechanics -> View Full Question like the article? email it to a friend.  
Author Message
me (120)

Hot goIITian

Olaaa!! Perrrfect answer. 18  [33 rates]

me's Avatar

total posts: 106    
offline Offline
EDITING
here is derivation -------------------
power is constant hence---------
F*v = k
m*a*v = k
m*dv/dt*v = k
m*v*dv = kdt
intagrating we get ------------
mv^2 = 2kt or
v = (2kt/m)^1/2
ds/dt = (2kt/m)^1/2dt
again intagrating
s =2/3(2k/m)^1/2 * t^3/2
or
s propor. to t^3/2
 this reply: 5 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
You have to be logged on to rate
  
 

Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Narayana - Kota , Delhi , Others
Brilliant Tutorials - Class , Crash
Aakash Institute - Medical , Engg
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya