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Discussion Response Post to: GP..problem....

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since

are the p^th,Q^th,R^th terms of G.P

=ar^p-1

^{=arQ-1 =ar}R-1 [R-1 in power] considering the two given vectors

as A &B A.B=(Q-R)log

³+(R-P)log

³+(P-Q)log

^{=3[(Q-R)l og+(R-P)log+(P-Q)log]}

^{log=loga+logr(P-1); log=loga+(Q-1)logr ; log =loga+(R-1)logr}

^{A.B=3[(Q-R)(loga+logr{P-1})+(R-P)(loga+(Q-1)logr+(P-Q)(loga+(R-1)logr)]}

^{=3[loga(Q-R+R-P+P-Q)+logr{(Q-R)(p-1)+(R-P)(Q-1)+(P-Q)(R-1)}]}

^{=3[0 +logr(0)]=0}

^{A.B=0 IMPLIES the angle between them is 90 degrees}

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