simple!!!! charge flown in 230 s = 1.7X230 C and with 90% efficiency = 1.7X230X0.9 C therefore moles of electrons released = 1.7X230X0.9 / 96500 moles = 3.64 millimoles now,
Zn2+ + 2e -----> Zn
this means Zn2+ converted into Zn = 1/2 of 3.64 = 1.82 millimoles
initially Zn2+ were 0.16 X 300 = 48 millimoles
hence Zn2+ left = 46.18 millimoles
so, concentration = 46.18/300 = 0.153933 M :)
LOKESH SARDANA,
department of Production and Industrial engineering,
Indian Institute of Technology,Roorkee.
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