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inverse functions...
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given sin-1(x/a)+sin-1(y/b)=  implies  -cos-1(x/a)-cos-1(y/b)=implies cos-1(x/a)+cos-1(y/b)= -.........(1)from(1)sin =y(a2-x2)1/2/ab+x(b2-y2)1/2/ab cos =(a2-x2)1/2(b2-y2)1/2/ab-xy/ab sin2( )=[x2b2+a2y2-2x2y2+(a2-x2)1/2(b2-y2)1/2 ]/a2b2 =x2/a2+y2/b2-2x2y2/a2b2+2xy/ab{(a2-x2)1/2(b2-y2)/ab} =x2/a2+y2/b2-2x2y2/a2b2+2xy/ab{cos +[xy/ab]}solving we get (c) as the result.
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