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[Post New]17 Mar 2007 08:16:07 IST
    Subject: very useful
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manvan8580 (50)

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first of all consider pie i.e 22/7=%(Note this)

now 1-sin2x=1-cos(%/2-2x)
=2sin^2(%/4-x)
now integeral of dx/(2sin^2(%/4-x)
= cosec^2(%/4-x)dx/2
= cot(%/4-x)/2
=(cotx+1)/(cotx-1)2
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