The answer for the question is l>m>n

First let us calculate the probabilities:

l is the probability of getting at least 2 black balls therefore the probability is (15c2+15c3+15c4)/25c4

m is the probability of getting atleast 1 white ball therefore the probability is (10c1+10c2+10c3+10c4)/25c4

n is the probability of getting atmost 3 white balls and 2 black balls, there are two conditions in this, the first condition means that we have to get maximum of 3 white balls in the drawn 4 balls and the second condition means that there should 2 black balls in the drawn 4 balls, therefore the probability is (10c1+10c2)/25c4

Since the denominator is common the we will make the relation considering the numerator.

l=1925/25c4

m=385/25c4

n=55/25c4

Therefore the relation l>m>n is correct.