IIT JEE , AIEEE Forum - Physics , Electricity

sriram.a

22)Hey dude a)E=kq/r^2 substitute and get

b)draw a perpendicular ot string let the angle be $\theta$ .

so sin $\theta$ =2.5/50=1/20.

Now the forces acting on the string r electric&weight forces.

Resolve along string &perpendicular to string.

component of Force along syring is balanced by tension so net force is 0 along the string.

along perpendicular $\frac{kq_1q_2}{r^2}cos\theta-mgsin\theta$ .Substitute and get value.

c)Tension= $\frac{kq_1q_2}{r^2}sin\theta+mgcos\theta$ .Substitute and get value.

d)From b)F=ma= $\frac{kq_1q_2}{r^2}cos\theta-mgsin\theta$ .Substitute and get the values

Cheeeeeeeeersssssssss