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varun.tinkle (1132)

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Olaaa!! Perrrfect answer. 200  [266 rates]

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LOOKING FROM THE FIGURE AND APPLYING CONSTRAINT EQUATION U CAN MAKE OUT THAT THE ACC OF THE MASS M IS TWICE THAT OF THE MASS 2M


SO IF THE ACC OF THE MASS 2M IS A THEN THAT OF THE MASS A IS 2A


I HV NOT GIVEN THE PROOF BUT IF U WANT I CAN


MG-T=M(2A)


2T=2MA  (SINCE IT IS CONNECTED TO 2 STRINGS AND IN EACH STRING THE MAGNITUDE OF THE TENSION IS T SO THE TOTAL TENSION IS 2T)


SOLVING IT WE GET ACC AS G/3


THEREFORE THE ACC OF THE MASS M IS (2G/3)


TENSION =MA =MG/3


THE FORCE EXERTED BY THE PULLEY =TENSION


BUT THERE R 2 TENSION FORCES ACTING AT AN ANGLE OF 90 OF MAGNITUDE MG/3


THEREFORE BY APPLYING SINE LAW


UNDER ROOT (MG)^2/9 +(MG)^2/9= 2(MG)^2/9


FORCE IS ROOT 2 MG/3


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