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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2007 12:13:06 IST
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A particle is projected from a point P(2,0,0) with a velocity 10m/s making an angle 45 degrees with the horizontal . The plane of projectile motion
through a horizontal line PQ which makes an angle of 37 degrees with the +ve X-axis, XY-plane is horizontal .The coordinates of the point where
the particle will strike the line PQ is (taking g=10m/(sec)2):-
(a) (10,6,0)
(b) (8,6,0)
(c) (10,8,0)
(d) (6,10,0)
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Ken
From: UNITED STATES, Green Bay, Wisconsin
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