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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 May 2008 11:27:46 IST
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i think the work done will be zero. coz. in removing the slab we have to do some external work lets say w and it will be positive tht is +w. now on reinserting the work will e done by the capacitor and will be w but with negative sign tht is -w. therefore the net work done will be zero.
RATE IF I M CORRECT.
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