IIT JEE , AIEEE Forum - Physics , Electricity

DON007

HEY LOOK............

WHEN A DIELECTRIC IS PUSHED

TWO CAPACITANCES ARE FORMED............

THAT IS.........

LET b be width that remains constant now l be length........

therefore c1= b(l-x)

C2= bkx

/D.........

C=C1+C2...........

U=1/2CV²

F= -dU/dx

F= -1/2V²dC/dx

bcoz only capaccitance is changing ...........

as ur answer is compete.............

but

FORCE=Keb V²(K-1)/2d

okkkkkkkkkkkkkk

hope u understands

there will be no effect of gravity..........i think so