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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: The equation of the parabola whose focus is the point (0,0) and the tangent at the vertex
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biki (1592)

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Olaaa!! Perrrfect answer. 284  [370 rates]

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first of all analyse the figure.


for the equation of a parabola, we need two important things.


1) the co-ordinates of focus


2) the equation of directrix.


Then, just equate the distance of any arbitratry point ( x, y ) on the parabola from directrix and the focus.


That is just the definition of the parabola.


Now the axis ofthe given parabola is perpendicular to the line y = x + 1


So the gradient of the axis = -1.


Again the axis passes through the origin ( 0, 0 ) which is also the focus.


So equation of axis => y = -x


Solving y = x + 1 and y = -x we get :-   x = -1/2 , y = 1/2.


So vertex of the parabola = ( -1/2, 1/2 )


So point of intersection of the axis and the directrix = ( -1, 1 ). This is because, vertex is the midpoint of the focus and the point where axis and directrix meet.


Slope of directrix = 1 ( since, parallel to y = x +1 )


Equation of directrix => y - 1 = 1. { x - (-1)} 


                                     => x - y + 2 = 0


So taking an arbitrary point (x, y ), we know that if its locus is to be that of a parabola, we must have :



Then square both sides to get the answer.


The answer will come out as :




salman khan
 this reply: 2 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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