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computer001 (1847)

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Olaaa!! Perrrfect answer. 297  [478 rates]

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area = 1/2 bsinA(c1+c2)


cosA=b^2+c^2-a^2/2bc


so c^2 -2bccosA +b^2-a^2=0


this is quad in c roots are c1 and c2


so c1+c2=2bcosA


so area = 1/2*bsinA*2bcosA


=1/2b^2sin2A


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