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Discussion Response Post to: probability

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Bipin Dubey (13679)

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Let he length of pieces be x,y,(1-x-y)

Now x>0 y>0 1-x-y>0 i.e.x+y < 1

Hence the area bounded by x=0, y=0, x+y=1 is 1/2.

Now applying the property of triangle that sum of two sides is greater than third side.

x + (1-x-y) > y gives y < 1/2

y+ (1-x-y) > x gives x < 1/2

x+y > 1-x-y gives x+y<1/2

Hence the area bounded by x=1/2, y=1/2, x+y=1/2 is 1/8.

Hence the required probability = (1/8)/(1/2) = 1/4

Bipin Kumar Dubey Chemical Dept. IIT Kharagpur

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