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differentiate and prove
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y =  (3x+2)dy/dx = (3/2)(3x+2)-1/2 d2y/dx2 = (-3/2)(3/2)(3x+2)-3/2 = (-9/4)(3x+2)-3/2 (dy/dx)2 = (9/4)(3x+2)-1 It gives y(d2y/dx2) + (dy/dx)2 = 0 and not d2y/dx2 + (dy/dx)2 = 0 as stated by you. |
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Bipin Kumar Dubey Chemical Dept. IIT Kharagpur |
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