ok for us only this reaction is important 2N2O5 gives 4NO2 so d[N205]/dt = (1/2)d[NO2]/dt i.e thr rate of change of conc of NO2 is twice the rate of change of conc of N2O5 now rate of change of conc of NO2= (2*10^-2)/5=4*10^-3 so rate of change of conc of N2O5= 2*10^-3 (ans)
please feel free to nudge me if you have any doubts
Moderation Team
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