Given f=12cm Object is at a distance of 19 cm from the lens and 21 cm in extreme.Now using lens formula u may calculate image distance for u=-19cm and u=-21cm. Clearly the image would oscillate between this two values. v=228/7=32.57cm and 252/9 =28cm Thus amplitude of vibration of image is (32.57-28)/2= 4.57/2=2.285 cm Please rate if satisfied....
Moderation Team
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