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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: find min a + b such that a+11b and a+13b are multiples of 13 and 11 resp. a,b>0
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pramod6990 (955)

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Olaaa!! Perrrfect answer. 175  [215 rates]

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my try.....


a + 11b=13m


a + 13b=11n


solving we have a= (169m-121n)/2


and b=(11n-13m)/2


and a+b =(156m-110n)/2...........1)


now as a>0 and b>0


we have.....   11/13> m/n>121/169


or 0.85 > m/n > 0.72


we take a favourable case of 0.75to get m and n as close to each other as possible so as to get the minimum value of the expression of 1)


due to which m/n=3/4.....m=3c and n=4c.......for integral values of a+b , c shud be even and 2 being the min evn number we have m=6 and n=8


using this we have min(a+b) as (936-880)/2 = 56/2 = 28....


so the minimum value of the expression (a+b) = 28.....


 


"Logic is the systematic way of reaching the wrong conclusion with confidence" lol.....
 this reply: 10 points  (with Olaaa!! Perrrfect answer.   in 2 votes )   [?]
 
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