%20=%20{sin}^{-1}%20(\frac{2x%2B2}{{(2x%2B2)}^{2}%2B{3}^{2}}))
Height = 2x+2 , hypotenuse = ((2x+2)2+32)1/2 so base = 3
If we convert in terms of tan, above expression =
= y (substitution)
tany = (2x+2)/3
dx = (3/2)sec2y.dy
so integral becomes
)
Do it by parts you'll get

Back substitute y to get the final result.
Edit : I forgot to add the constant of integration.