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computer001 (1849)

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Olaaa!! Perrrfect answer. 297  [479 rates]

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chinmay...both ur answers are right..


1st consider..


answer a :log[sin(pi/4 +x)] + c


answer b: log[rt2sin(pi/4+x)] + d {i am using 'd' to indicate tht it is  a diff constant}


answer b can be written as log(rt2)+log[sin(pi/4 +x)] +d as logab=loga+logb


thts all.. the 'c' u got in the 1st case is equal to 'd' + log(rt2)..thts the only diff!!!


 


the mistake u have made is tht u have considered c,d as the same which is not true in this case


 


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