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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Jun 2008 23:27:09 IST
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ok now my method....1/x-x^3=1/x(1-x^2)
so now let logx = t,,,so we will get i/xdx=dt,,,
so dt/(1-e^2t) ,,,now we can integrate this by using .....dx/a^2-x^2=1/2loga+x/a-x+c,,,,,
so the answer i m getting is 1/2log(1+x/1-x)+c...is it correct,,,?
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