Flux on the opp face is Q/24 epsilon.

consider 8 cubes. so flux at one of its face will be Q/6 Epsilon. and one face is consist of 4 small cubes. so net flux on the required face will be Q / 24 Epsilon.

Flux on the face in which it is placed will be Zero. because electric lines of force will be in the direction perpendicular to the area vector which is normal to the surface area. so net flux will be equal to 0

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