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[Post New]8 Jun 2008 16:28:52 IST
    Subject: Re:Solutions of triangle
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allamraju (3435)

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Olaaa!! Perrrfect answer. 607  [807 rates]
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We know,b=2RsinB and c=2RsinC.I substituted them and took 4R2 common.Now,I wrote sin2B-sin2C as sin(B+C)sin(B-C)=sinAsin(B-C).


Now,I used 2sinCcosD=sin(C+D)+sin(C-D).I think now you understood.
MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC.
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