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Discussion Response Post to: mixed questions

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Bipin Dubey (13679)

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The possible combinations and no. of ways for product of three integers to be 30 are given as :

(1,1,30)    no. of ways = 3!/2! = 3

(1,2,15)    no. of ways = 3! = 6

(1,3,10)    no. of ways = 3! = 6

(1,5,6)    no. of ways = 3! = 6

(2,3,5)    no. of ways = 3! = 6

Hence total no. of ways = 27

Please post your other queries on a new page.

Bipin Kumar Dubey Chemical Dept. IIT Kharagpur

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