IIT JEE , AIEEE Forum - Physics , Mechanics

varun.tinkle

SO MANY ANSWERS AND SO MUCH CONFUSION
SEEE DUDES IT ACCORDING TO WHAT I UNDERSTAND
THE QUES IS ASKING THE LOSS OF KINETIC ENERGY IN THE SYSTEM
SO
ASSUMING THE SAND BAG WAS INITIALL AT REST
BOTH THE MASSES ARE MOVING WITH THE SAME VELO
SO
mV=(M+m)V2
V2=mV/(m+M)
INITIAL .E. OF THE BULLET=1/2mV^2
FINAL K.E.=1/2(M+m)(mV/(m+M))^2
=1/2(mv)^2/M+m
SO LOSS IN K.E.
CAN BE EASILY CALCULATED
PLS RATE ME IF U FIND ME USEFUL
!!!!!!!!!CHEERS!!!!!!

Ask & Discuss Questions with Community & Experts