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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Jun 2008 15:13:27 IST
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(a+b+c)=0
(a+b+c)^2=0
a^2+b^2+c^2= -2(ab+bc+ac)
1=4(ab+bc+ac)^2
1=4 {b^2c^2+a^2b^2+a^2c^2)+8abc(a+b+c)
1/2=2{b^2c^2+a^2b^2+a^2c^2)
now
(a^2+b^2+c^2)^2=a^4+b^4+c^4+2{b^2c^2+a^2b^2+a^2c^2)
a^4+b^4+c^4=1-1/2=1/2...............:)
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