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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Jun 2008 13:44:19 IST
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Tell the mass of precipitate obtained.
Moles of NacL in sample = moles of AgCl ppt = mass of ppt/MM of AgCl
Mass of NaCl in sample = Moles of NaCl*MM of NaCl
Percentage of NaCl = 100*Mass of NaCl/2
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
this reply: 5 points
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