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hsbhatt (4973)

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Olaaa!! Perrrfect answer. 937  [1081 rates]

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While, the arguments presented above are intuitively correct, they are not rigorous enough.


Consider the function g(x) = f(x) - x which is also a continuous function.


Now, if either f(0) = 0 or if f(1) = 1, then we are done.


Now, if f0)  0 and f(1) 1, then f(0)>0 and f(1)<1 (Since range of f is [0,1] for the domain [0,1])


i.e. f(0)-0>0 and f(1) -1<0.


i.e. g(0)>0 at x =0 and g(1)<0 at x =1


Since g(x) is continuous, from Bolzano's Theorem also called Intermediate Value Theorem,


g(c) = 0 for some x[0,1].


This means f(c) - c =0 or f(c) = c


Time wounds all heels
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