hey there i hav gt anothr method

check this out.....

first we hav 2 find the S in terms of u nd g



lets hav CASE 3 first.......



u=0 a=g S will be v^2 /2g...........



and time will be T3 = v / g



CASE 1 ...



LETS FIND THE DIST THE BODY TRAVELS UPWARS

u = u v = 0 a = -g S1 is u^2 / 2g nd t1 = u / g

nw the dist the body has 2 travel downwrd will be S1 + S = v^2 / 2g + u^2 / 2g = v^2 + u^2 / 2g



time it will take = t2 = root v^2 + u^2 / g  



T1 = t1 +t2 = root v^2 + u^2 + u / g



CASE 2 .....

 u = u a = g S = v^2 / 2g  

T2 = root v^2 + u^2 - u / g



nw by the values of T1 , T2 , AND T3 WE EASILY GET THE REQUIRED RELATION ........

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