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Discussion Response Post to: Integral Trouble

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23 Mar 2007 12:30:34 IST

Subject: Re:Integral Trouble

iitkgp_bipin (6498)

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When you will draw the curves x⁴ and 2x² they intersect at (0,0) ; (

2) ; (-

2)

In the 1st quadrant there are two areas one of which is from x = 0 to x =

2 and is bounded and one is unbounded from x =

2 to

Similarly in the 2nd quadrant there are two areas one of which is from =0 to x= -

2 and is bounded and one is unbounded from x = -

2 to -

.

Accordingly set your values of a and b for minimum and maximum.

Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur

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