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Plz solve this problem
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For image formation due to M1, 1/f=1/u+1/v Here f=20cm , u=30cm So v=60cm Let distance of S from M2 be x. The image due to M1 acts as virtual object and this virtual object will be at a distance =60-(30+x)=30-x For M2 f= -20cm , u= -(30-x)=x-30 and v= x So using 1/f=1/u+1/v We get x=20cm a)So distance between two mirrors is 30+20 =50cm b)Use 1/f=1/u+1/v Here f= -20cm , u=20cm So v= -10cm
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-ADARSH NITK Surathkal |
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