IIT JEE , AIEEE Forum - Physics , Electricity

prasen_prasen

i know the solution only for the first part
in this the perpendicular distance between each equipotential surface is d=10 cos30 =>5cm.(and this is same 4 all the surfaces)
converting into meters we have 0.5m
we know that E=V/d
applying this for each we have
E(1)=20 E(2)=40 E(3)=60 E(4)=80
hence the total E=E(1)+E(2)+E(3)+E(4)=20+40+60+80=200V/m

coming to the direction the electric field is always perpendicular to the equipotential surfaces.
hence its direction is 120 degrees with +ve X- axis

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