Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: permutation problems plz solve
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Priyesh (1601)

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Hi Abhijeet
ans to 4)
let us consider ABCD to be in order. now we have to insert 2 people between them.
1st case: the other two persons(E&F) will be together 
_ _ A _ _ B _ _ C _ _ D _ _
no.of ways 5C1*2!=10 ways
2nd case : the other two persons will not be together
 
_  A _  B _ C _ D _
no. of ways 5C2* 2!=20 ways
total ways=10+20=30
 
the mistake made by kvenkan was that if we insert the other people in position 1 & 5 or 2 & 5(see fig below) there is no difference in the arrangement.
 
12A34B56C78D910
 
 
Hope you understood

 
 
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