@x4 SEE, THIS SYSTEM COULD NOT BE CALLED A CAPACITOR. BECAUSE FIRST OF ALL THE CHARGE IS ONLY GIVEN TO ONE PLATE AND AT THE SECOND PLATE THE CHARGE IS INDUCED WHICH CAN NEVER BE LIKE CHARGE. NOW IF U WANT A SYSTM LIKE THIS U HAVE TO CHARGE BOTH THE PLATES SIMULTANEOUSLY THEREFORE THIS IS LIKE CHARGING TWO DIFFERENT CONDDUCTORS SIMULTANEOUSLY. NOW AS FAR AS UR DERIVATION GOES ON, U MUST FIRST OF ALL KEEP IN CONSIDERATION THE FACT OF USING THE FORMULA C = Q/V IN THIS V IS NOT THE POTENTIAL DIFFERENCE BUT THE ABSOLUTE POTENTIAL OF THE CONDUCTOR. NOW KEEPING THIS FACT IN MIND U CAN SEE THT DUE TO THE PRESENCE OF OTHER SIMILARLY CHARGED PLATE THE POTENTIAL AT FIRST PLATE IS ACTUALLY INCREASED SINCE POTENTIAL IS A SCALER QUANTITY AND THEREFORE ALGEBRAIC SUM WILL BE DONE. THEREFORE DUE TO INCREASE IN POTENTIAL THE ACTUAL CAPCITY IS DECREASED NOT INCREASED.
Moderation Team
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