Chemical Kinetics Problems
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q1--- fraction of molecules of reactants having energy equal to or greater than activation energy= e^(-E/RT) put the values n get the answer q3--- k=Ae^(-E/RT) k=2.418 * 10^-5 E=179.9 kJ/mol T=546 K R=0.0821 now put these values and get the value of A hope it helps... |
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Who says nothing is impossible. I've been doing nothing for years !!.............. I know KUNG FU KARATE and 47 other dangerous words............. |
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