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[Post New]22 Jun 2008 11:15:52 IST
    Subject: Re:the number of roots of
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hsbhatt (4888)

Forum Expert Blazing goIITian

Olaaa!! Perrrfect answer. 922  [1061 rates]
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venkat has the better approach:


z^3 + \bar{z} = 0 \Rightarrow z^3 = - \bar{z} \Rightarrow |z|^3 = |-\bar{z}| = |z|


This means either z = 0 or |z| = 1


|z| = 1 \Rightarrow \bar{z} = \frac{1}{z}


The equation simply becomes z^4 = -1 which has 4 complex roots


Thus total number of roots is 5
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