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solve this - Quadratic Equations
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3 sol) since a,b &c,d are roots of x2+px+1=0 &x2+qx+1=0 respectively, a+b=(-p), ab=1 c+d=(-q) cd=1 c2+qc+1=0 d2+qd+1=0 now (a-c)(b-c)(a+d)(b+d)=[ab-(a+b)c+c2][ab+(a+b)d+d2] =[1+pc+c2][1-pd+d2]=[pc-qc][-pd-qd]=(-cd)[p-q][p+q] =(-1)[p2-q2]=q2-p2
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